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overflowonline
.grande:maestro.

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Numeri complessi

ho questa eqauzione:

z^6 +1 = 0

Mi chiede:
Determinare tutte le soluzioni in forma trigonometrica e algebrica.


pi=pigreco

Procedimento:
z^6= -1
scrivo l'equazione in forma trigonometrica:

z^6 = 1 * (cos(pi) + i * sin(pi))

Ok ora io troverei le soluzioni in questo modo:


z^6 = 1^6 *( cos(pi*6) + i * sin(pi*6))

Zn = 1 *{cos[(pi *6+ 2Kpi)/6] + i * sin[(pi *6 + 2Kpi)/6]}

Con n=6 e K= da 0...a 5

Mi spiegate dove sbaglio???? al prof viene:

Zn = 1 * {cos[(pi\6+ (2Kpi)\6)] + i * sin[pi\6 + (2Kpi)\6]}

Grazie ciaooo

Last edited by overflowonline on 26-06-2005 at 17:07

26-06-2005 17:04
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torak
Renaulto muori

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caspita, chi è l'artefice? De falco?

27-06-2005 07:56
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Skilotto83
..Energia positiva...

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Originally posted by torak
caspita, chi è l'artefice? De falco?



:asd:

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27-06-2005 08:08
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