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People
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esercizio3su:"esercizi-rtng-06-07"

cioè questo kome si fà???
se avete problemi sui primi 2 li ho fatti facilmente!

18-01-2007 17:14
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People
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ok ci sono arrivato..
nn lo avevo mai visto..
allora si prendono i vettori in ordine partendo da quello kol delay+basso.
il kosto da C al nodo ke gli manda il DV è = al Delay [pensavo invece fosse = al valore del vettore alla posizione C].
costruisci il DV sommando il kosto del nodo ke manda il vettore [quindi il delay] ai valori del DV arrivato..
se nn è kiaro:
- A B C D E F
D 16 12 6 0 9 10 -->delay 3

risultato
C 19 15 0 3 12 13
da D D C D D D

poi prendo il vettore kol delay appena superiore
A B C D E F
E 7 6 3 9 0 4 -->delay 5

E modificano i valori solo se migliori

risultato
C 12 11 0 3 5 9
da E E C D E E

E POI KN L ULTIMO IL RISULTATO VIENE
C 11 6 0 3 5 8
da B B C D E B

o sbaglio??

Last edited by People on 18-01-2007 at 17:47

18-01-2007 17:44
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Andrej
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Ciao.
Avrei un gran dubbio, nell'esercizio a pag 5 numero 14:
oltre all'header tcp non si contano i 20 dell'header ip?
Grazie dell'aiuto!

18-01-2007 23:27
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People
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lo faccio stamattina poi posto la mia soluzione su un altro thread..

19-01-2007 09:09
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