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Strong
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Chiarimento operatori logici

Salve,
volevo chiedervi un chiarimento, in particolare è l'esercizio 2 dello scritto del 2 marzo 2011.
Esattamente non ho capito questa parte:

int x = 4;
int y = 3;
boolean b = (x>=(x>y++) ? x++ : y++);

sostituendo i valori nella condizione si ha:
4>=(4>3) [e y diventa 3]

ora, nella parentesi il risultato dovrebbe essere un boolean con risultato true, e ora mi chiede se 4>= di un true? sbaglio a ragionare? qualcuno me lo spiega? thanks!

20-01-2012 15:06
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Strong
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*modifica [e y diventa 4, scusate].

20-01-2012 15:07
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Strong
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Risolto da solo.
Le parentesi ingannano, equivale a dire boolean b = x>=x>y++ ? x++ : y++;
Quindi 4>=4>3 ? true :)

20-01-2012 16:04
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oksana213
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Dato:
int x = 4;
int y = 3;
boolean b = (x>=(x>y++) ? x++ : y++);

Passo 1.
int x=4; int y=3;
(x>y++) ? x++ : y++, i.e. 4>3? SI, e incrementiamo x.

Passo 2.
int x=5; y=4 (y si è incrementato dopo la valutazione x>y++)
x>=(...)?, i.e.5>=5? SI.

Passo 3.
boolean b=TRUE.

Risultato finale:
int x = 5;
int y = 4;
boolean b = TRUE;

27-01-2012 20:04
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Strong
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Originally posted by oksana213
Dato:
int x = 4;
int y = 3;
boolean b = (x>=(x>y++) ? x++ : y++);

Passo 1.
int x=4; int y=3;
(x>y++) ? x++ : y++, i.e. 4>3? SI, e incrementiamo x.

Passo 2.
int x=5; y=4 (y si è incrementato dopo la valutazione x>y++)
x>=(...)?, i.e.5>=5? SI.

Passo 3.
boolean b=TRUE.

Risultato finale:
int x = 5;
int y = 4;
boolean b = TRUE;


Grazie ma avevo già risolto.

28-01-2012 20:44
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