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Steve Harris
Hallowed be thy Name

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Help Esercizi

Un generatore audio in tecnica table look-up utilizza una tablella di 1024 campioni ed opera a 16 bit e 44100 Hz di campionamento. Quale è la frequenza minima che può produrre senza utilizzare l’interpolazione?
a) 96 dB
b) 43 Hz
c) 0,023 Hz
d) 1,024 Hz

chi sa spiegarmi perchè la risposta è 43 Hz....
grazie:-D

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19-06-2006 20:51
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Nicolaij
.primate.

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qualcuno di voi lo sa fare...io me lo sento...
e steve paga in natura a chi rispa ^^

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20-06-2006 00:09
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nasa85
.arcimaestro.

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allora:

la durata del periodo è 1024 x(1/44100),quindi la frequenza è 44100/1024 che è uguale a 43 HZ

20-06-2006 08:19
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