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.dsy:it. : Powered by vBulletin version 2.3.1 .dsy:it. > Didattica > Corsi N - Z > Sistemi operativi I > [SIS. OP. - BRUSCHI] Info 2004/05 Thread Rating: 1 votes, 3.00 average.
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Dante
JUANES

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Perchè la prima lettera che può stampare è per forza la b.

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12-04-2005 15:45
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Dante
JUANES

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Cmq, se l'esame è come gli anni scorsi, e mi sembra di aver capito così, sarà un bel terno al lotto...

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Sometimes you hurt the ones who love you most and sometimes you hold the ones who leave you lost,
and sometimes you learn
but its too late, it's too late. EI

12-04-2005 15:47
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michelez
.precettore.

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Originally posted by Dante
Perchè la prima lettera che può stampare è per forza la b.


non e' vero, i semafori generalizzati non assicurano alcun ordine di esecuzione dei processi e quindi non puoi sapere se viene schedulato prima il processo che stampa A o il processo che stampa B

12-04-2005 15:49
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elpampero
Aniversario

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Un processo utente durante la propria esecuzione:

A. viene eseguito costantemente in kernel mode
B. viene eseguito in una modalita' dipendente dai privilegi dell'owner
C. viene eseguito costantemente in user mode
D. puo' essere eseguito in kernel mode


Qual è????

12-04-2005 15:51
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Dante
JUANES

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Originally posted by michelez
non e' vero, i semafori generalizzati non assicurano alcun ordine di esecuzione dei processi e quindi non puoi sapere se viene schedulato prima il processo che stampa A o il processo che stampa B


questa cosa nn l'ho trovata sul libro... mi arrendo...

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and sometimes you learn
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12-04-2005 15:54
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michelez
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Originally posted by elpampero
Un processo utente durante la propria esecuzione:

A. viene eseguito costantemente in kernel mode
B. viene eseguito in una modalita' dipendente dai privilegi dell'owner
C. viene eseguito costantemente in user mode
D. puo' essere eseguito in kernel mode


Qual è????


Dovrebbe essere la D, nel senso che le system call sono eseguite in kernel mode.

12-04-2005 15:59
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elpampero
Aniversario

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Tranquillo Dante, qualche post i dietro c'e' spiegato perchè è C.

Michelez, teoricamente non ci sono altre operazioni oltre a quelle dello scheduler che possono mettere in ready un processo run..a essendo non-preemtive questo non può mai verificarsi

12-04-2005 16:00
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elpampero
Aniversario

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e perchè non la B? un processo di sistema non gira in Kernel mode?

12-04-2005 16:01
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michelez
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Ah Ok, per la mia 5.


Nella domanda che hai posto si chiede in che modalità gira un processo utente. Gira in modalità utente nelle computazioni normali, mentre, se esegue system call, passa in modalità kernel(che non c'entra con i provilegi di esecuzione).


Sto uscendo dal lavoro, riprendiamo la chiaccherata domani. :)
Ciao

12-04-2005 16:06
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shadow
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Ragazzi ho letto che il compitino inizierà alle ore 10.30 circa, ma si sa quanto durerà?
Dove posso reperire qualche domanda dell'anno scorso, oltre quelle postate qui sul forum.
Ciao a tutti e grazie.

12-04-2005 17:00
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nothingman7
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ciao volevo chiedervi un aiutino..
secondo voi qual è la risposta a questa domanda?

1) In un sistema multithread quale, tra le seguenti risorse, e' condivisa tra tutti i thread di un processo:

A. PC
B. file
C. registri
D. stack

12-04-2005 17:04
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Dante
JUANES

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Per shadow: vai all'area filez del dsy sotto la sez sistemi operativi.

Per nothingman7: B. File

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Sometimes you hurt the ones who love you most and sometimes you hold the ones who leave you lost,
and sometimes you learn
but its too late, it's too late. EI

12-04-2005 17:14
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shadow
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grazie dante

12-04-2005 17:15
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Dante
JUANES

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prego!

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Sometimes you hurt the ones who love you most and sometimes you hold the ones who leave you lost,
and sometimes you learn
but its too late, it's too late. EI

12-04-2005 17:25
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nothingman7
.amico.

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immaginavo..grazie dante

12-04-2005 18:17
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