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.dsy:it. : Powered by vBulletin version 2.3.1 .dsy:it. > Didattica > Corsi A - F > Calcolo delle probabilità e statistica matematica > Esame 15 Febbraio
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pragers
.arcimaestro.

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sul sito di informatica autogestita dovrebbe essercene uno....
12-02-2007 17:59
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pragers
.arcimaestro.

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Ragazzi in bocca al lupo a tutti...:razz:
14-02-2007 16:44
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dirkpitt
Il Laureando...

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 Talking

crepi!!

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Esistono 10 tipi di persone al mondo: quelli che conoscono il codice binario e quelli che non lo conoscono... :D
14-02-2007 16:45
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danire83
.primate.

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crepiiii :evil:
14-02-2007 16:54
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imperator
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crepi
14-02-2007 17:21
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nasa85
.arcimaestro.

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crepi cazzo!!!!!!!!!!!!!!!!!!!!
14-02-2007 18:08
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ayu
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crepi !
14-02-2007 20:00
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not103
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oramai stì lupi saranno protetti dal wwf... crepi!
14-02-2007 21:56
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pragers
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bhe a sto punto mi faccio l'imbocca al lupo da solo (crepi) dato che tutti hanno detto "crepi" ma nessuno "altrettanto":D

Ha ah ha...ora vado a dormire che domani mi aspetta una dura prova:(
15-02-2007 01:47
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vlaste
Tecnoclassico

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Qualcuno ha svolto il punto IV.3 (segnato erroneamente sul testo come IV.2, insomma quello di "si avvicina una nevicata":asd: )?
E l'esercizio V?
15-02-2007 13:21
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imperator
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io il IV.3 l'ho risolto usando la legge debole dei grandi numeri...non so ancora come ho fatto ma ho tirato fuori una boiata del genere...
P(-0,05 < Wn - 0,5 < 0,05) >= 1 - c2

il V invece nn ho fatto in tempo a farlo...

qualcuno sa dire di preciso come si svolgevano questi due esercizi?

Last edited by imperator on 15-02-2007 at 14:29
15-02-2007 14:25
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LoneWolf
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In area filez ci sono tema e soluzioni, date un 'occhiata.

Non ho capito la storia dei risultati: vengono messi su internet o solo fuori dal suo ufficio?!?
Io domattina parto e non posso andarci al suo ufficio... qualcuno guarda per me se l'ho passato e quando ho l'orale?

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15-02-2007 15:05
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LoneWolf
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Originally posted by imperator
io il IV.3 l'ho risolto usando la legge debole dei grandi numeri...non so ancora come ho fatto ma ho tirato fuori una boiata del genere...
P(-0,05 < Wn - 0,5 < 0,05) >= 1 - c2

il V invece nn ho fatto in tempo a farlo...

qualcuno sa dire di preciso come si svolgevano questi due esercizi?

Dovevi approssimare il risultato con la distribuzione normale, praticamente facendo:
P(Wn-0.5<0.05) - P(Wn-0.5<-0.05) =
= Φ(0.05) - Φ(-0.05) =
= Φ(0.05) - [1 - Φ(0.05)] =
= 2Φ(0.05) - 1

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"It is totally natural to die or to be killed, rather than just to live without a certain purpose"
15-02-2007 16:46
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n3o
tanto c'è SPASS...

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Originally posted by LoneWolf
Dovevi approssimare il risultato con la distribuzione normale, praticamente facendo:
P(Wn-0.5<0.05) - P(Wn-0.5<-0.05) =
= Φ(0.05) - Φ(-0.05) =
= Φ(0.05) - [1 - Φ(0.05)] =
= 2Φ(0.05) - 1


mmm...
per me era da fare in questo modo:

La media aritmetica delle ascisse differisca in valore assoluto da 0,5 metri per meno di 5 centimetri

p = P(|0,5 - W| < 0,05) = P(-0,05 < 0,5 - W < 0,05) =
= P(-0,05 - 0,5 < -W < 0,05 - 0,5) = P(-0,55 < -W < -0,45) =
= P(0,45 < W < 0,55)

Z = W* standardizzato:

p = P((0,45 - 0,5)/(1/sqrt(240)) < Z < (0,55 - 0,5)/(1/sqrt(240))) =
= (-0,7746 < Z < 0,7746) = Φ(0,7746) - Φ(-0,7746) =
= 2Φ(0,7746) - 1 = 0,5614

c2 = c1 (1 - p) / p = 1 * (1 - 0,5614) / 0,5614 = 0,782 €

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The answer is blowing in the wind...

Last edited by n3o on 15-02-2007 at 20:22
15-02-2007 20:18
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vlaste
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Originally posted by n3o
mmm...
per me era da fare in questo modo:

[...]

Z = W* standardizzato:

[...]

Perchè standardizzi? Il mood (teorema 3.14 pag. 120) non dice che la variabile casuale in oggetto deve essere standardizzata...

EDIT: in ogni caso il risultato mi viene lo stesso, a meno di approssimazioni alla terza cifra decimale

Last edited by vlaste on 16-02-2007 at 15:37
16-02-2007 15:29
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