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.dsy:it. : Powered by vBulletin version 2.3.1 .dsy:it. > Didattica > Corsi A - F > Elaborazione numerica dei segnali > Esame Dsp Thread Rating: 1 votes, 4.00 average.
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Lunik
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e daje no!
Fratto 2

scusa
arctg -1/0 = arctg - infinito

nel grafico dell'arcotangente il meno infinito verso cosa va? PGreco mezzi....

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17-02-2003 16:54
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JaM
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si, trasformando il -i = e^(-i*p/2)

ma poi lo moltiplichi per e^(i*p/4) e ottieni e^(-i*p/4)
17-02-2003 17:01
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Lunik
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ma xè devo moltiplicarlo per e^(i*p/4) ????

guarderò domani...ora sto sclerando troppo.
cià!

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17-02-2003 17:02
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JaM
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hai il coeff c5 = -i*e^(i*p/4) = e^(-i*p/2) * e^(i*p/4) = e^(-i*p/4)
17-02-2003 17:04
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Lunik
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mmmm non ricordo la formulettadegli esponenti..non dovrei moltiplicare p/2 con p/4?

:wall:

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17-02-2003 17:08
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JaM
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no, si sommano, rifaccio con il passaggio intermedio:

c5 = -i*e^(i*p/4) = e^(-i*p/2) * e^(i*p/4) = e^(i*(-p/2 +p/4)) = e^(-i*p/4)
17-02-2003 17:11
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Lunik
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si si sommano scusa...non so xè ho scritto moltiplicano!!! :pensa:

si allora ci siamo....JaM per favore posta tu la correzione di questo coefficiente nell'area fileZ...
tnx...
ciao!

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17-02-2003 17:13
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dilix
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:pensa:
Ma a che serve tutto ciò? Cosa si trova?
17-02-2003 17:15
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Lunik
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si trova che il coefficiente c-5 = 1 e ha fase -p/4

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17-02-2003 17:16
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fantasim75
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il tesoro.... :)

ecco cosa si trova...
17-02-2003 17:16
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Lunik
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Originally posted by fantasim75
il tesoro.... :)

ecco cosa si trova...


:lol: magari!!! :asd:

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fantasim75
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saremo tutti + ricchi....

:?
17-02-2003 17:17
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fantasim75
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ricchi dentro certo...

:(
17-02-2003 17:17
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Lunik
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Off-Topic:
uh? xè il broncio???? :smack:

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17-02-2003 17:18
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dilix
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Ma perché per ogni coefficiente quindi bisogna trovare la fase, giusto? Qual è la formula per trovare la fase? :?
17-02-2003 17:18
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