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.dsy:it. : Powered by vBulletin version 2.3.1 .dsy:it. > Didattica > Corsi A - F > Elaborazione numerica dei segnali > Esame Dsp Thread Rating: 1 votes, 4.00 average.
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Lunik
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:approved:

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16-02-2003 19:34
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Lunik
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Piuttosto nel primo esercizio veniva un - 1/i
lo moltiplico e divido per i e ottengo i
ma questo deve essere tradotto in forma esponenziale...sarò mezza rimba ora..ma giuro che con le formule non saprei come ricavare il numero esponenziale...
Perchè la prof dice che i = e ^i pGreco/4

p.s. ^ è elevato

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16-02-2003 19:37
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imation
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guarda che dovrebbe essere e^(i*p/2)

... per ricavarlo basta scriverlo in forma goniometrica e poi esponenziale:
-in forma goniometrica: i = (cos(p/2)+i*sin(p/2)) = e^(i*p/2)
16-02-2003 19:53
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Lunik
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Ah ora va bene!!! Se è piGreca/2 allora mi è chiaro...non capivo il 4!
Grazie!

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17-02-2003 08:21
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JaM
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uan moment.... io lo avevo calcolato in un altro modo e mi era venuto proprio i = e ^(i*pGreco/4)

cioe': a + i*b = r e^(i*teta)

dove r = radiceQuadrata(a^2 + b^2) = 1

teta = arctg(b/a) = arctg(1) = pGreco/4


e' il metodo sbagliato???
17-02-2003 09:40
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Lunik
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ahi no...hai:
arctg 1/0
ma 1/0 è infinito
quindi
arctg di infinito è PiGreco mezzi...
prendi il grafico dell'arcotangente...

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17-02-2003 09:43
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JaM
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azz... e' vero.... che pirla che sono..... :sbonk:
17-02-2003 09:45
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Lunik
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Si questo lo sappiamo :D

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17-02-2003 09:47
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JaM
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:grr: :grr: :grr:

attenta che prima o poi il mostro mangia criceti arriva :rotfl:
17-02-2003 09:50
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Lunik
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Originally posted by JaM
:grr: :grr: :grr:

attenta che prima o poi il mostro mangia criceti arriva :rotfl:


:ueee::ueee:

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17-02-2003 09:57
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JaM
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:P

(per non farlo sembrare un reply spammoso aggiungo un po' di parole tra parentesi :D )
17-02-2003 10:02
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Lunik
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:D
sto facendo il primo esercizio dei coefficienti....mi manca ancora qualche passaggio...e poi lo posto.
Ah non so fare la seconda parte di questo esercizio...chiede la funzione g(x)...
se qualcuno la sa fare...la posti!!!

grazie!

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17-02-2003 10:09
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JaM
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Applichi un filtro passa alto che taglia a 4,5w0

quindi scompaiono i componenti con 2w0 e 4w0 perche' non li lascia passare e restano quelli con 5w0 e 7w0
17-02-2003 10:18
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Randall
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Originally posted by JaM
Applichi un filtro passa alto che taglia a 4,5w0

quindi scompaiono i componenti con 2w0 e 4w0 perche' non li lascia passare e restano quelli con 5w0 e 7w0


OK, questa parte l'avevo capita, più o meno.
Ma quello che devi scrivere alla prov cos'è?
La funzione privata delle componenti che "non passano"?
O basta in linguaggio discorsivo quello che hai detto tu?

Ah, essendo una bestia in matematica (e tra l'altro, Istituzioni non l'ho ancora fatta..) ho provato a leggere i post sopra sulla i ma ho deciso da saltarli...
:-PPP

Ciao
Ste

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17-02-2003 10:25
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Lunik
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i numeri complessi sono facilissimi!!!! Devi solo applicare quelle 3, 4 formulette e basta...e sapere un po' di trigonometria!

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17-02-2003 10:27
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