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.dsy:it. : Powered by vBulletin version 2.3.1 .dsy:it. > Didattica > Corsi G - M > Matematica del discreto > [TONOLLI] es 2°compitino
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walder
.consigliere.

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 [TONOLLI] es 2°compitino

Scusate ma dove sn le soluzioni agli esercizi in preparazione al secondo compitino della tonolli? Sul suo sito nn li vedo.
07-01-2007 18:31
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simo555
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ecco,pure io ne avrei bisogno.. Per il primo compitino aveva messo le soluzioni!

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09-01-2007 15:03
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walder
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Dai ragazzi nessuno che posta le proprie soluzioni? Domani comincio a postare le mie, confrontiamole e risolviamo i dubbi!
10-01-2007 19:13
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Pupino
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Originally posted by walder
Dai ragazzi nessuno che posta le proprie soluzioni? Domani comincio a postare le mie, confrontiamole e risolviamo i dubbi!


Io purtroppo di quei fogli so fare ben poco!!

Avendo preso 15 nel primo, mi basta prendere 3 di teoria e magari un esercizio, quindi mi concentro solo su una o due tipologie...

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10-01-2007 19:51
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Pupino
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Ga)
VERA


Gb)
La trasposta è questa:
-2 3 -1 0
3 -5 1 -7

Gc) Non ammette inversa in quanto il determinante è 0

Gd) La sua inversa è (ho fatto la prova ed è giusta)

4/11 -1/11
-1/11 3/11




Se faccio altro lo posto! ;)

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11-01-2007 17:49
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Pupino
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Na)

A me viene così, ma sono molto guardingo, POSTATE LA VOSTRA!

k = 3 infinite ^1 soluzioni
k=-2 nessuna soluzione
k diverso 3 1 soluzione


Nb)

Indeterminato



Sarà giusto? :please:

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Last edited by Pupino on 12-01-2007 at 09:44
11-01-2007 18:43
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walder
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bella :approved:
12-01-2007 09:50
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Pupino
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Originally posted by walder
bella :approved:


Bella = Giuste ?

o

Bella = Grazie ?


:asd:

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12-01-2007 09:57
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walder
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entrambe ^_^
12-01-2007 10:09
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Pupino
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suuuuuuuuuuuuuuuuuperrrrrrrr!!! :banana:

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12-01-2007 10:22
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walder
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Originally posted by Pupino
Na)

A me viene così, ma sono molto guardingo, POSTATE LA VOSTRA!

k = 3 infinite ^1 soluzioni
k=-2 nessuna soluzione
k diverso 3 1 soluzione


Nb)

Indeterminato



Sarà giusto? :please:



Stavo riguardando e mi sn accorto che nn mi esce la soluzione per k=-2 :?
Da dove arriva?
13-01-2007 09:59
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ss672629
Nekogal - Miao

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ma ragazzi mi confermate che l'appello è stato spostato al 30 gennaio al posto del 25???????

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13-01-2007 13:27
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ayakochan
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Originally posted by Pupino
Na)

A me viene così, ma sono molto guardingo, POSTATE LA VOSTRA!

k = 3 infinite ^1 soluzioni
k=-2 nessuna soluzione
k diverso 3 1 soluzione


Nb)

Indeterminato



Sarà giusto? :please:


scusa la domanda idiota...ma per indeterminato cosa intendi?
io ho provato a farlo e mi viene:

| x=(5-z)/10
| y=(6-7z)/10
| z=z

dove ho sbagliato???
se non ti scoccia mi scrivi il procedimento che hai usato?
sono in alto mare [..per poi lasciarsi andareeee..]

:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?

thank you soooo much

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13-01-2007 23:58
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walder
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e cmq a me nn salta fuori per x = -2 ...
Per indeterminato penso che intenda dire che ha soluzioni che dipendono dal parametro z (che potevi porre = h per esempio),le soluzioni le trovi con cramer ed escono anche qui esattamente quelle 3.
Volendo essere + precisi pure per x diverso da 3 ci sarebbe da trovare con cramer un'unica soluzione, operando su una matrice 3 x 3.
14-01-2007 10:09
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lele19871
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Ciao,
non sono del vostro turno ma ho provato a risolvere il problema O.
Mi risulta:
a=b) | 1 0 0 0 |
| 2 1 0 0 |
| 0 0 2 0 |
| 0 0 0 1 |
c) im f = car F = 4 poichè det !=0
d) ker f= 0
14-01-2007 10:51
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