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.dsy:it. : Powered by vBulletin version 2.3.1 .dsy:it. > Didattica > Corsi N - Z > Ricerca operativa > Appello 05/04/2006
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nic
.illuminato.

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Appello 05/04/2006

ecco..partiamo dal 2 come sempre ;-)

qui abbiamo una variabile libera.. bisogna stare attenti sia nello scrivere la forma standard sia nel duale...

11-02-2007 15:36
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DarkStalker
.consigliere.

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Intanto posto il grafico giusto per precauzione :)

Attachment: out.pdf
This has been downloaded 13 time(s).

11-02-2007 16:02
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DarkStalker
.consigliere.

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Merda ho sbagliato appello AAAARGH!
Ho preso quello del 13/04/05

11-02-2007 16:08
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ripe
- up in the mountains -

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* POST CANCELLATO *

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«And if you ever smell christian blood up in the mountains, then get your axe and chop them down!»

Last edited by ripe on 11-02-2007 at 16:36

11-02-2007 16:12
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DarkStalker
.consigliere.

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Ho un dubbio atroce, a me risulta che il vertice ottimo per via grafica sia (0,-2)
ma non dovrebbe essere degenere dato che x2 non e' libera in segno?

11-02-2007 16:20
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ripe
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Merda! Ho risolto il problema di massimo, ma era di minimo...

Se faccio un errore del genere all'esame mi ammazzo!
Ora correggo tutto!

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«And if you ever smell christian blood up in the mountains, then get your axe and chop them down!»

11-02-2007 16:28
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DarkStalker
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Niente come non detto mi sono accorto di una cappellata, sto perdendo colpi :P
Non puo' essere 0,-2 perche' ho il vincolo x2 > 0

11-02-2007 16:29
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ripe
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Originally posted by DarkStalker
Ho un dubbio atroce, a me risulta che il vertice ottimo per via grafica sia (0,-2)
ma non dovrebbe essere degenere dato che x2 non e' libera in segno?


(0, -2) è un pò difficile perchè x2 deve essere maggiore o uguale a 0!

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11-02-2007 16:31
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DarkStalker
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Me ne er0 accorto ;)
Dovrebbe ora essere (-1,0)

11-02-2007 16:32
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ripe
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L'es 2 è bastardo, spero di non averlo cannato del tutto! :(
Corretto!

2.1.

z = -1
x1 = -1
x2 = 0
x3 = 16
x4 = 4
x5 = 0

2.2

-2 <= b3 <= 30

2.3

min z = x1 + - x1- + x2

-x1+ + x1- + 3x2 + x3 = 15
2x1+ - 2x1- - x2 + x4 = 2
-2x1+ + 2x1- - x2 + x5 = 2
xi >= 0 per ogni i

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«And if you ever smell christian blood up in the mountains, then get your axe and chop them down!»

11-02-2007 16:35
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ripe
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Originally posted by DarkStalker
Me ne er0 accorto ;)
Dovrebbe ora essere (-1,0)


Ho visto tardi la tua risposta... ora è giusto!

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11-02-2007 16:36
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ripe
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Anche il 3 non mi convince molto... :asd:

max 15y1 + 2y2 + 2y3

-y1 + 2y2 - 2y3 = 1
3y1 - y2 - y3 >= 1
y1, y2, y3 >= 0

Y* = (0, 0, -1/2, -1/2)

Il sistema risolto è:

-2y3 = 1
-y3 - y4 = 1

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«And if you ever smell christian blood up in the mountains, then get your axe and chop them down!»

Last edited by ripe on 11-02-2007 at 17:14

11-02-2007 16:40
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DarkStalker
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ok per ora viene cosi' anche a me il 2

11-02-2007 16:56
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DarkStalker
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Questa 3y1 - y2 - y3 >= 2 non dovrebbe essere invece <= 1 (stai passando da min a max e il coeff di costo di x2 e' 1)?

11-02-2007 17:05
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ripe
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Originally posted by DarkStalker
Questa 3y1 - y2 - y3 >= 2 non dovrebbe essere invece <= 1 (stai passando da min a max e il coeff di costo di x2 e' 1)?


E' maggiore o uguale a 1... hai ragione, che disastro!

(maggiore o uguale, perchè x2 >= 0)

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11-02-2007 17:12
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